an object 4cm in size is placed at a distance of 25cm in fronf of a convex mirror of radius of curvature 40cm. find the position size and nature of image
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h= 4cm
u =-25
R = 40
f = 40/2
=20
1/v+1/u=1/f
1/v= 1/20+1/25
= 5+4/100
= 9/100
therefore , v = 100/9
nature of an image is virtual ,erect...
u =-25
R = 40
f = 40/2
=20
1/v+1/u=1/f
1/v= 1/20+1/25
= 5+4/100
= 9/100
therefore , v = 100/9
nature of an image is virtual ,erect...
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