An object 4cm tall is placed on the pricipal axis of a concave mirror of focal length 20 cm at a distance of 30cm from it.find the position. nature and size of the image.
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Ho = 4cm
F = -20. [ sign convention]
U= -30 [ sign convention]
Using mirror formula,
1/U + 1/V = 1/F
1/(-30) + 1/V = 1/(-20)
1/V = 1/-20-1/(-30)
1/V = 1/20-1/30
1/V = 3-2/60
1/V = 1/60
V =60cm
Thus image is formed at a distance of 60 cm from the concave mirror. Since V is positive, so image is formed behind the concave mirror.Iy means the nature of image is virtual and erect.
F = -20. [ sign convention]
U= -30 [ sign convention]
Using mirror formula,
1/U + 1/V = 1/F
1/(-30) + 1/V = 1/(-20)
1/V = 1/-20-1/(-30)
1/V = 1/20-1/30
1/V = 3-2/60
1/V = 1/60
V =60cm
Thus image is formed at a distance of 60 cm from the concave mirror. Since V is positive, so image is formed behind the concave mirror.Iy means the nature of image is virtual and erect.
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