Question

An object 4s size is placed at 50cms infrount of a concave mirror of focal length30cms. find the image distance and also height of the image?​

Answer 1

Answer:

It’s at the centre of curvature since R = 2f So the image is real, same place as object but inverted.

Using the Formula, and the RIP convention (Real Is Positive)

Everything is real, therefore positive

1/v + 1/u = 1/f

1/v + 1/60 = 1/30

1/u = 1/60

u = +60

M = v/u = +1 and the + here signifies an inverted image.

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