Question

an object 5.0 cm in legth is placed at a distance of 20 in front of a convex mirror of radius of curvature30cm. find the position of the image ots nature n size​

Answer 1

Answer:

v=8.57cm size-+2.14cm...errect and diminshed

Explanation:

radius of curvature=f/2

therefore focal length=15cm

distance of object(u)=20cm

using mirror formula:

1/f=1/v+1/u

1/v=1/f-1/u

=1/15+1/20

=4+3/60

=7/60cm

v=60/7cm

=8.67 cm

image is virtual errect and behind the mirror.

Magnification=-v/u=h'/h

h'/5=-8.67/-20

h'=8.67×5/20

h'=15/7=+2.14

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