Question

An object 5.0 CM in length is placed at a distance of 10 cm from a convex mirror of radius of curvature 1 50 cm. Find the position, nature and size of the image.​

Answer 1

Answer:

Given: u=−20 cm

f=R/2=15 cm

Size of image, h=5 cm

Let size of image be h ′

From mirror formula,

1/v +1/u = 1/f

1/v = 1/f – 1/u

1/v = 1/15 – 1/-20

v = 8. 57 cm

Image is virtual and erect and formed behind the mirror.

m = -v/u

m = h'/ho

hi/5= 8.57/20

= 0.428

h' = 0.428 x 5 = 2.14cm

Position of Image: Behind the mirror.

Nature of Image: Virtual and Erect.

Size of the Image: Diminished.