Question

an object 5.0 CM in length is placed at a distance of 20 CM in front of a convex mirror of radius of curvature 30cm find the position of the image​

Answer 1

Radius of curvature (R) = 30 cm

f = R/2 = 30/2 = 15 cm

u = -20 cm,

h= 5 cm.

1/v +1/u = 1/f

1/v = 1/f – 1/u

1/v = 1/15 – 1/-20

v = 8. 57 cm

Image is virtual and erect and formed behind the mirror.

m = -v/u

m = hi/ho

hi/5= 8.57/20

= 0.428

hi = 0.428 x 5 = 2.14cm

HOPE IT WILL HELP YOU

Answer 2

Answer:

Given: u=−20 cm

f=R/2=15 cm

Size of image, h=5 cm

Let size of image be h

From mirror formula,

u/1 + v/1 = f/1

1/-20+ v/1 = 15/1

v= 7/60 =8.57 cm

The image is formed 8.57cm behind the mirror. It is virtual and erect.

Magnification, m=−v/u=8.57/20=0.428

Also, m=h /h=h /5

From above, h /5=0.428

h =2.14 cm