Question

An object 5.0 cm in length is placed at a distance of 20cm in front of a convex mirror of radius of curvature 30cm .Find the position of the image , its nature and size?​

Answer 1

Answer:

height of object = 5 cm

f=15 cm

u=-20cm

therefore,

1/v=1/f-1/u

=1/15+1/20

=7/60

so v =60/7

therefore height of image=60/7 x 20=3/7

so the image is virtual,erect and smaller in size by 3/7th of its original size.