An object 5.0 cm in length is placed at a distance of 20cm
in front of a convex mirror of radius of curvature 30cm find the position of the image its nature and size
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we know,
1/v + 1/u = 1/f
1/v = 1/15 + 1/20( R = 2f)
1/v = 7/60
v = 8.57 cm
nature = virtual and erect
height = 8.57 / 20 x 5
= 2.1 cm
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