Question

an object 5.00 cm high is placed 10 cm from a convex mirror with a focal length of magnitude 8 cm , find the position of the image

Answer 1

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U= -10 cm

f= 15 cm

1/f = 1/v + 1/u

So, 1/v= 1/f - 1/u

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Therefore v=5/30 = 6 cm

Hence the image is formed behind the mirror and therefore it is virtual and erect

Answer 2

Answer:

U= -10 cm

f= 15 cm

1/f 1/v+1/u

So, 1/v= 1/f-1/u

1/v 1/15+ 1/10

1/V = (2+3)/30 (lcm)

Therefore v=5/30 = 6 cm

Hence the image is formed behind the

mirror and therefore it is virtual and erect.