An object 5.0cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image,its nature and size.
Answers
Answered by
5
Answer:
Radius of curvature (R) = 30 cm
f = R/2 = 30/2 = 15 cm
u = -20 cm,
h= 5 cm.
1/v +1/u = 1/f
1/v = 1/15+ 1/20 = 7/60
v = 60/7 = 8.6 cm.
Image is virtual and erect and formed behind the mirror.
hi/h0= v/u
hi/5= 8.6/20
hi = 2.2 cm.
Size of image is 2.2 cm.
Answered by
1
Given: u=−20 cm
f=R/2=15 cm
Size of image, h=5 cm
Let size of image be h
′
From mirror formula,
u
1
+
v
1
=
f
1
−20
1
+
v
1
=
15
1
v=
7
60
=8.57 cm
The image is formed 8.57cm behind the mirror. It is virtual and erect.
Magnification, m=−v/u=8.57/20=0.428
Also, m=h
′
/h=h
′
/5
From above, h
′
/5=0.428
h
′
=2.14 cm
Similar questions