an object 5 cm high is kept 25 cm away from a convex lens of focal length 10cm. What is the nature,position and size of the image. plz and it soon
DibyarchanaParichha:
is here any one to ans me
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Hey!!!!!
For a convex lens, We have
h = 5cm
u = -25cm
f = +10cm
v = ?
m = ?
h' = ?
Thus By lens formula
1/f = 1/v - 1/u
=> 1/10 = 1/v + 1/25
=> v = 50/3
=> v = + 16.6cm
Now m = +v/u
=> m = 16.66/25
=> m = - 0.6
Thus image will be real, inverted and diminished.
Now m = h'/h
=> -0.6 = h'/5
=> h' = -3cm
Hope this helps
For a convex lens, We have
h = 5cm
u = -25cm
f = +10cm
v = ?
m = ?
h' = ?
Thus By lens formula
1/f = 1/v - 1/u
=> 1/10 = 1/v + 1/25
=> v = 50/3
=> v = + 16.6cm
Now m = +v/u
=> m = 16.66/25
=> m = - 0.6
Thus image will be real, inverted and diminished.
Now m = h'/h
=> -0.6 = h'/5
=> h' = -3cm
Hope this helps
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