Question

An object 5 cm high is placed at a distance 60 cm
in front of a concave mirror of focal length 10 cm.
Find (i) the position and (ii) size, of the image.​

Answer 1

h e r e,

object distance=-60cm

focal length=-10 centimetre

so,1/image distance=1/-10 - 1/-60

=-1/10 + 1/60

= 1-6/60

=-5/60

so, image distance =-60/5= -12 cm

since, magnification = - image distance/object distance=image height\object height

so,-(-12)/-60=image height/5

image height= - 5/5 =-1 cm

so,

1. position of image is at 12 cm in front of mirror.

and 2. size size of image is 1 cm and is real and inverted.