Question

An object 5 cm high is placed at a distance 60 cm in front of a concave mirror of focal length 10 cm.
Find
(i) the position and
(ii) size, of the image​

Answer 1

Answer:

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Answer 2

Answer:

✈Question✈

An object 5 cm high is placed at a distance 60 cm in front of a concave mirror of focal length 10 cm.

Find

• (i) the position and
• (ii) size, of the image

✈Answer✈

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✍Given✍-

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• Size of the object height (h°)= 5cm
• Focal length of mirror(f)= -10cm
• Object distance (u)= -60cm

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✍To find-

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• Image position=Image distance(v)=???
• Size of image(hi)=???

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✍Solution✍-

Using the formula of mirror

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

=>$\frac{1}{-10}=\frac{1}{-60}+\frac{1}{v}$

=>$\frac{1}{-10}-\frac{1}{-60}=\frac{1}{v}$

=>$\frac{-6+1}{60}=\frac{1}{v}$

=>$\frac{-5}{60}÷1=v$

=>v=$\frac{\cancel{60}}{\cancel{-5}}$

=>v=-12 cm

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Hence, position of the image is 12 cm in the mirror.

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As, we know:

Magnification (M°)=$\frac{hi}{h°}=\frac{-v}{u}=\frac{-(-12)}{-60}=-0.2$

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A/Q

hi=-0.2×h°

=>hi= 0.2× 5= -1 cm

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Hence, height of the image is 1 cm.