Question

An object 5 cm high is placed at a distance of 15 cm from a concave mirror of radius of

curvature 20 cm. The height of the image is cm

(A) 5 cm (B) 20 cm (C) 15 cm (D) 10 cm​

Answer 1

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10%

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30%

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50%

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100%

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ANSWER

Here is a proper solution to the problem:

Here is a proper solution to the problem:We are given R = 20 cm. Then f = R/2 = 10 cm.

Here is a proper solution to the problem:We are given R = 20 cm. Then f = R/2 = 10 cm.Use the mirror formula: 1/10 = 1/15 + 1/Di → Di = 30 cm.

Here is a proper solution to the problem:We are given R = 20 cm. Then f = R/2 = 10 cm.Use the mirror formula: 1/10 = 1/15 + 1/Di → Di = 30 cm.The image distance being positive means that it is REAL. Real images are INVERTED.

Here is a proper solution to the problem:We are given R = 20 cm. Then f = R/2 = 10 cm.Use the mirror formula: 1/10 = 1/15 + 1/Di → Di = 30 cm.The image distance being positive means that it is REAL. Real images are INVERTED.The magnification is (30 / 15 = 2 x). The image is MAGNIFIED, and located on the same side as the object.

Here is a proper solution to the problem:We are given R = 20 cm. Then f = R/2 = 10 cm.Use the mirror formula: 1/10 = 1/15 + 1/Di → Di = 30 cm.The image distance being positive means that it is REAL. Real images are INVERTED.The magnification is (30 / 15 = 2 x). The image is MAGNIFIED, and located on the same side as the object.Since the mag is 2 X, the height of the image (its size) is: 5 x 2 = 10 cm.

so,the answer is d)10 cm

Note-googled it

Source-google

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Answer 2

Answer:

the above answer is correct