An object 5 cm in height is placed a distance of 10 cm from a cancave mirror of radius of curvature 30 cm . find the nature positive sizw of the images
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HEYA!
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u=-10 cm for convex mirror, the object distance is -ve.
v=?
R= 30 cm
f =15 cm
ho= 5 cm
1/u+1/v=1/f
(-1/10)+(1/v)=(1/15)
1/v=1/15+1/10
1/v=(2+3)/30
1/v =5/30
v= 6 cm
size of the image
m= hi/ho =-v/u
=-6/10 =0.6
0.6=hi/5
hi=3 cm
The image is formed at a distance of 6 cm behind the mirror, virtual, upright and smaller than the object.
size of the image is 3 cm.
GOOD EVENING!
u=-10 cm for convex mirror, the object distance is -ve.
v=?
R= 30 cm
f =15 cm
ho= 5 cm
1/u+1/v=1/f
(-1/10)+(1/v)=(1/15)
1/v=1/15+1/10
1/v=(2+3)/30
1/v =5/30
v= 6 cm
size of the image
m= hi/ho =-v/u
=-6/10 =0.6
0.6=hi/5
hi=3 cm
The image is formed at a distance of 6 cm behind the mirror, virtual, upright and smaller than the object.
size of the image is 3 cm.
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