Question

An object 5 cm in length is held 25cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.

Answer 1

Answer:

Image is real, inverted, diminished and forms between $F_2$ and $2F_2$

Explanation:

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Answer 2

Answer :

Height of object = 5cm

Distance of object = 25cm

Focal length = 10cm

Type of lens : converging (convex)

We have to find

• Position of image
• Size of image
• Nature of image

★ Focal length of convex lens is taken positive and that of concave lens is taken negative$.$

★ Distance of image :,

Distance of image can be calculated by using lens formula which is given by

• 1/v - 1/u = 1/f

v denotes distance of image

u denotes distance of object

f denotes focal length

By substituting the given values, we get

➠ 1/v + 1/u = 1/f

➠ 1/v + 1/(-25) = 1/10

➠ 1/v = 1/10 + 1/25

➠ 1/v = 7/50

➠ v = 7.14 cm

★ Size of image :

➠ m = v/u = h'/h

• h' denotes height of image
• h denotes height of object

➠ 7.14/(-25) = h'/5

➠ h' = -7.14/5

➠ h' = 1.428 cm

Negative sign shows that image is inverted.

★ Nature of image :

• Real
• Inverted
• Short