Question

an object 5 cm in length is placed at a distance of 20 CM in front of a convex mirror of radius of curvature 30cm find position nature and the size of the image formed

Answer 1

Size of the object O = 5cm, u =20cm, f=r/2=30/2=15cm

hence by mirror formula,

1/f=1/v+1/u

1/15=1/v+1/20

1/v=1/15 -1/20

hence, v=60 cm

it means a virtual and erect image is formed behind the mirror and size of the image,

m= -V/U=I/O

I =( -V/U)× O

= -60×5/20

=-15 CM

hope this helps........let me know

Answer 2

HEY MATE HERE IS YOUR ANSWER

HEIGHT OF OBJECT=5 CM

f = 15 cm

u =-20 cm

therefore,

1/v=1/f-1/u

= 1/15 +1/20

= 7/60

so v = 60/7/20=3/7

so the image is virtual, erect and smaller in size by 3/7th of its original size..


HOPE IT HELPS U
MARK AS BRAINLIEST...