An object 5 cm in length is placed at a distance of 30 cm in front of a convex mirror of radius of curvature 40 cm. Find the position of the image, its nature and size.
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Step-by-step explanation:
Height of object=5cm
f=15 cm
u=-20cm
therefore,
1/v=1/f-1/u
=1/15+1/20
=7/60
so v =60/7
therefore height of image=60/7/20=3/7
so the image is virtual,erect and smaller in size by 3/7th of its original size
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