Question

an object 5 cm in length is placed at distance of 20 CM in front of a convex mirror of radius of curvature 30cm find the position of image its nature and size

Answer 1

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Answer 2

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Your Answer -

Given :

Object distance, u = -20 cm

Object height, h = 5 cm

Radius of curvature, R = 30 cm

Focal length, f = R/2 = 15 cm

☑ Mirror Formula :

According to the mirror formula,

1/v + 1/u = 1/f

1/v = 1/f - 1/u

1/v = 1/15 - ( - 1/20 )

1/v = 1/15 + 1/20

1/v = (3+4)/60

1/v = 7/60

v = 8.57 cm

➡ The positive value of v indicates that the image is formed behind the mirror.

☑ Magnification :

m = - v/u = - ( 8.57/-20) = 0.428

➡ The positive value of magnification indicates that the image formed is virtual.

Now again,

m = h'/h { h' is image height }

h' = m × h

h' = 0.428 × 5 = 2.14 cm

➡ The positive value of h' is indicates that the image formed is erect.

☑ Hence, the image formed is erect, virtual, and smaller in size.

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