An object 50 cm tall is placed on the principal axis of a convex lens. Its 20 cm tall image is formed on the screen placed at a distance of 10 cm from the lens. Calculate the focal length of the lens?
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Given-
h₁=50cm
h₂=20cm
v=10cm
To Find-
focal length (f)
sol-
m=h₁/h₂=v/u (Magnification)
we get,
u=vh₁/h₂
=10*50/-20
u=(-25cm)
now,
1/v-1/u=1/f (Lens Formula)
=1/10-1/(-25)
LCM=250
=25+10/250
=250/35
f= 7.14cm
Hence the focal length is 7.14cm
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