Question

An object 50 mm high standard on axis of concave mirror of focal length is 100 mm at a distance of 300 mm from concave mirror. How big image will formed

Answer 1

Answer:

f=100mm

u=300mm

h1=50mm

1/v+1/u=1/f

1/v+1/300=1/100

1/v=1/100 - 1/300

1/v= -1/200

v= -200

M=h2/h1= -v/u

h2=u/h1v

= 300/50(-200)

=-0.03mm

Hence, the height of image would be -0.03. The negative sign indicates that the image is on left side of concave mirror. And the image is inverted real and diminished.