An object 50cm tall is placed on the principal axis of a convex lens.its 20 cm image is formed on the screen placed at a distance of 10 cm from the lens. Calculate the focal length of the lens
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hey
magnification(m) = hi/ho
m = 20/50
m = 2/5
2/5 = 10/u
u = 50/2
u = 25cm
by using lens formula ,
1/f = 1/v - 1/u
1/f = 1/-10 - 1/25
1/f = -5 - 2 / 50
1/f = -7/50
f = 50/-7
f = - 7.1cm
mercy10robert11:
I'm sorry I voted wrong.tq so much
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