Question

an object 5cm high forms a virtual image of 1.25cm high, when placed in front of aconvex mirror at a distance of 24 cm.calculate:a.the position of the image b.the focal length of the mirror

Answer 1

from mirror Formula
1/V+1/U=1/F
magnification =-v/u=4
u=-24
putting values by sign convention and solving we get f=32cm