An object 5cm high is placed at a distance of 10cm from a convex mirror of Radius of Curvature 30cm. Find the size of the image.(in cm)
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Given mirror is convex mirror
f = R/2= 30/2=15
u= -10 cm
h= 5 cm
Now, we have to find the nature , position ,and size of image.
Thus using mirror equation
1/f= 1/u+ 1/v
1/v = 1/f - 1/u
1/v = 1/15 + 1/10
1/v = 25/150
v= 6 cm (hence image will be formed between focus and pole)
Now magnification,
m = -(v/u) = (h'/h)
m = -(-6/10) = 3/5
=3/5(image will be virtual , erect ,and diminished)
Now again,
m= h'/h
3/5 =h'/5
h'= hence the size of image will be 3 cm.
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