An object 5cm high is placed at a distance of 30cm from a converging lens of focal length 15cm. Find the nature and position of image.( Include steps)
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Answer:
Height of object, h
o
=5cm, object distance u=−30cm, focal length f=−20cm
Now, from mirror formula :
f
1
=
v
1
+
u
1
v
1
=
f
1
−
u
1
=
20
−1
+
30
1
=−
60
1
v=−60cm - image distance
Magnification, m=−
u
v
=−
−30
−60
=−2
Size of image, h
i
=m(h
o
)=−2(5)=−10 cm
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