an object 5cm high is placed at a distance off 10 cm from a convex mirror of radius of curvature 30 cm . find the nature , size, position of the image
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given object size= 5cm
object distance ,u = 10cm
radius of curvature =30cm
then Focal length ,f= 30/2 =15cm
now by mirror formula,
1/v + 1/u =1/f ----- 1/v = 1/f -1/u
1/v = 1/15 - 1/10 ---- 1/v =15-10/150
1/v = 1/30---- v=30cm
m= -v/u = -30 /10 =then m = -3cm
and nature = real and inverted
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