an object 5cm in lenght is placed at a distance of 20cm in front of a convex mirror of radius of curvature 30cm.find the position of the image,it's nature and size.
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object is 5cm length is 20 cmradius is 30cm=
20×30×5=3000
20×30×5=3000
jacob9:
sry it's terribly a wrong answer...
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the formula is
1/f = 1/v+ 1/u
f = R/2
= 30/2
= -15cm
u =- 20cm
and
v= ?
after solving we get
v = -60cm
and the nature of image is real inverted and enlarged
and to find the height the formula is
-v/u = image height / object height
and after solving we get
image height is 15 CM
1/f = 1/v+ 1/u
f = R/2
= 30/2
= -15cm
u =- 20cm
and
v= ?
after solving we get
v = -60cm
and the nature of image is real inverted and enlarged
and to find the height the formula is
-v/u = image height / object height
and after solving we get
image height is 15 CM
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