Question

An object 5cm in length is placed at a distance of 20cm in front of a convex mirror of radius of curvature 30cm.Find the position of the image, its nature and size.​

Answer 1

Answer:

Radius of curvature (R) = 30 cm

f = R/2 = 30/2 = 15 cm

u = -20 cm,

h= 5 cm.

1/v +1/u = 1/f

1/v = 1/15+ 1/20 = 7/60

v = 60/7 = 8.6 cm.

Image is virtual and erect and formed behind the mirror.

hi/h0= v/u

hi/5= 8.6/20

hi = 2.2 cm.

Size of image is 2.2 cm

Answer 2

Explanation:

An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.

Radius of curvature (R) = 30 cm

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cm

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f1/v = 1/15+ 1/20 = 7/60

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f1/v = 1/15+ 1/20 = 7/60v = 60/7 = 8.6 cm.

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f1/v = 1/15+ 1/20 = 7/60v = 60/7 = 8.6 cm.Image is virtual and erect and formed behind the mirror.

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f1/v = 1/15+ 1/20 = 7/60v = 60/7 = 8.6 cm.Image is virtual and erect and formed behind the mirror.hi/h0= v/u

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f1/v = 1/15+ 1/20 = 7/60v = 60/7 = 8.6 cm.Image is virtual and erect and formed behind the mirror.hi/h0= v/uhi/5= 8.6/20

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f1/v = 1/15+ 1/20 = 7/60v = 60/7 = 8.6 cm.Image is virtual and erect and formed behind the mirror.hi/h0= v/uhi/5= 8.6/20hi = 2.2 cm.

Radius of curvature (R) = 30 cmf = R/2 = 30/2 = 15 cmu = -20 cm,h= 5 cm.1/v +1/u = 1/f1/v = 1/15+ 1/20 = 7/60v = 60/7 = 8.6 cm.Image is virtual and erect and formed behind the mirror.hi/h0= v/uhi/5= 8.6/20hi = 2.2 cm.Size of image is 2.2 cm.

Hope helped you .