Question

An object 5cm in length is placed at a distance of 20cm in front of the 30cm. Find the position, size and nature of the image

Answer 1

Answer:

Formula:

v1+u1=f1

Given,

v1+(−20)1=151

v1=607⇒v=760

v=8.57≈8.6cm

The image is formed behind the mirror at a distance of 8.6 cm 

m=h1h2=−uv

→5h2=−208.57

∴h2=2.175 cm

Thus the image is 2.175 cm high, virtual and erect.

Hence, this is the answer.