Question

An object 5cm is lenght is placed at a distance of 20cm in front of a convex mirror of radious of curvature 30cm find position nature size of image

Answer 1

height "h"=+5cm         u=-20 cm    r=30cm

therefore, focal length f = r/2=30/2=-15cm

1/v=1/f-1/u

    =1/-15-1/-20 = 1/-15+1/20=5/300 = 1/60

therefore, f=60 cm

magnification m =v/u=60/-20=-3

height of image h'=vh/u=60*5/-20=300/-20=-15cm

therefore the image is real, inverted, and enlarged, and appears at a position of 60 cm away from the mirror