An object 6.0 c.m. tall is placed on the principal axis of convex lens . It's 3.0c.m. tall image is formed on the screen placed at a distance of 30 cm from the lens , the focal length of the lens is
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We know that,
Magnification m=- v/u=h'/h=30/20
and also v=10cm
So u=-20/3 cm
Using formula,
1/v -1/u=1/f
1/10 + 1/(20/3)=1/f
or f=4 cm
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.
.
do follow n mark it as brainlist if it is helpful
Magnification m=- v/u=h'/h=30/20
and also v=10cm
So u=-20/3 cm
Using formula,
1/v -1/u=1/f
1/10 + 1/(20/3)=1/f
or f=4 cm
.
.
.
do follow n mark it as brainlist if it is helpful
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