An object 6 cm in size is placed at
30 cm infront of concave mirror The
of curvature is 40cm. Find the
nature and size of image.
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Explanation:
Given,
Radius of curvature, R=40cm
Object distance, u=30cm
Object height, h
o
=3cm
The focal length of the mirror=f=−
2
R
=−20cm
From mirror equation,
v
1
+
u
1
=
f
1
⟹
v
1
+
−30
1
=
−20
1
⟹v=−60cm
The magnification, M=
u
−v
=−
−30
−60
=−2
Hence the image is inverted, enlarged, real and its size is 2×3cm=6cm.
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