Physics, asked by sathyanarayanatalari, 17 days ago

An object 6 cm in size is placed at
30 cm infront of concave mirror The
of curvature is 40cm. Find the
nature and size of image.​

Answers

Answered by ElegantBoi
1

hope it's helpful...

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Answered by bhavyapanda20
1

Explanation:

Given,

Radius of curvature, R=40cm

Object distance, u=30cm

Object height, h

o

=3cm

The focal length of the mirror=f=−

2

R

=−20cm

From mirror equation,

v

1

+

u

1

=

f

1

v

1

+

−30

1

=

−20

1

⟹v=−60cm

The magnification, M=

u

−v

=−

−30

−60

=−2

Hence the image is inverted, enlarged, real and its size is 2×3cm=6cm.

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