Question

An object 60 cm tall is placed on the principal axis of a convex lens and its 30 cm tall
is formed on the screen placed at a distance of 40 cm from the object. What is the focal length of the lens?​

Answer 1

Answer:

here is ur answer

Explanation:

"According to the given details, we can take the value of h as 60 cm

H1 = -30 cm

V + u = 40 cm

H1/h = V/u

60/-30 = v/u

-2 = v/u

V = -2u

-2u = u = 40 cm

-u = 40 cm

U = -40 cm

V = -2 x -40

V = 80 cm

We need to find the focal length

1/F = 1/80 + 1/40

1/F = 1+ 2/80

1/F = 3/80 cm

F = 80/3

F = 26.67 cm

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