An object 6cm in height is placed at a distance of 5cm from concave mirror of focal length 10cm find the position ,nature and height of the image?
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Here is ur answer.........
The virtual and erect image will be formed 10cm behind the mirror.
Height of the image = -v/u × h
= -10/-5 × 6
= 2 × 6
= 3 cm.
Hope it helps!!☺☺
The virtual and erect image will be formed 10cm behind the mirror.
Height of the image = -v/u × h
= -10/-5 × 6
= 2 × 6
= 3 cm.
Hope it helps!!☺☺
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