Question

an object 7 cm size is placed at 25 cm in front of a concave lens of focal length 15 cm at what distance should be screen place find nature and the size of the image formed​

Answer 1

Answer:

v = -9.375cm

h' = 2.625cm

nature - virtual and erect

Step-by-step explanation:

lens - concave

h = 7cm

u = -25cm

f = -15cm

1/f = 1/v - 1/u

1/v = 1/f + 1/u

1/v = (1/-15) + (1/-25)

1/v = (1/-15)*5 + (1/-25)*3

1/v = (-5/75) + (-3/75)

1/v = (-8/75)

v = -75/8

v = -9.375cm

h'/h = v/u

h'/7 = -9.375/-25

h'/7 = 0.375

h' = 2.625cm

nature - virtual and erect