Question

An object 'A' of mass 2kg moving with a velocity of 3m/s collides head on with object 'B' of mass 1kg moving in the opposite direction with a velocity of 4m/s.After collision both bodies stuck together and move with a common velocity.find it's velocity . ( plz proper steps)

Answer 1

Given data:

Object of Mass A (m1) = 2 Kg, For the second object B (m2)= 1 Kg; velocity of object A u1 = 3 m/s, In the question, it is given that after collision, the object b tend to move with mass 1 kg in opposite direction with velocity u2= 4 m/s;

Solution: m1u1 + m2u2 = (m1+m2) v = 2*3 – 1*4 = 3V. Velocity v= 2/3 m/s.

Answer 2

Answer:

2/3 m/s

Explanation:

M1=2kg

M2=1kg

initial velocity of M1=3m/s

initial velocity of M2=4m/s

applying law of conservation of momentum

M1V1+M2V2=M1U1+M2U2

since final velocity is same

V(M1+M2)=M1U1+M2U2

V(2+1)=2*3+1*(-4)(negative because in the opposite direction)

V*3=6+(-4)

V*3+6-4

V*3=2

V=2/3

hence the answer is 2/3 m/s.