Question

an object accelerate from rest to a velocity 30m/s in 10 s then find the distance covered by the object in next 10 sec​

Answer 1

Answer:30 m/s

Explanation:as u = 0 m

And v=30 m and t= 10 sec

Then by v= u +at

30 = 0 + a × 10 s

30/10 = a

A = 3m/s²

Now.. For another 10 sec

By v= u + at

V = 30 + 3×10

V = 60 m

The final position of the object is 60m

And the distance travelled in another 10 sec is 30 metres

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