Question

An object accelerates from 8.5 m/s to rest in 3 seconds. Solve for the object's acceleration.

$\large \boxed{ \: \: \: a = \frac{ {v}_{f} - {v}_{o}} { \triangle t} \: \: \: \: \: }$​

Answer 1

Answer:

• -2.83 m/s² is the required acceleration of the object.

Explanation:

According to the Question

It is given that,

• Initial velocity,u = 8.5m/s
• Final velocity ,v = 0m/s
• Time taken ,t = 3

we have to calculate the acceleration of the object.

As we know that acceleration is defined as the rate of change in velocity at per unit time.

• a = ∆v/t

→ a = v-u/t

substituting the value we get

→ a = 0-8.5/3

→ a = -8.5/3

→ a = -2.83m/s

here,

negative sign show thatacceleration is retarding .

• Hence, the acceleration is -2.83m/s².

Answer 2

Given :-

• An object accelerates from 8.5 m/s to rest in 3 seconds.

To Find :-

• What is the object's acceleration.

Formula Used :-

$\clubsuit$ Acceleration Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{a =\: \dfrac{v_f - v_o}{\triangle t}}}}\: \: \: \bigstar$

where,

• a = Acceleration (m/s²)
• $\sf v_f$ = Final Velocity (m/s)
• $\sf v_o$ = Initial Velocity (m/s)
• $\sf \triangle t$ = Time Taken (seconds)

Solution :-

Given :

• Initial Velocity = 8.5 m/s
• Final Velocity = 0 m/s
• Time Taken = 3 seconds

According to the question by using the formula we get,

$\implies \sf\bold{\blue{a =\: \dfrac{v_f - v_o}{\triangle t}}}$

$\small \implies \bf a =\: \dfrac{Final\: Velocity - Initial\: Velocity}{Time\: Taken}$

$\implies \sf a =\: \dfrac{0 - 8.5}{3}$

$\implies \sf a =\: \dfrac{- 8.5}{3}$

$\implies \sf\bold{\red{a =\: - 2.83\: m/s^2}}$

$\small \sf\bold{\purple{\underline{\therefore\: The\: required\: object's\: acceleration\: is\: 2.83\: m/s^2\: .}}}$

[Note :- The negetive sign of acceleration denotes that it is retardation. ]

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