Question

An object accelerates from rest to 85 m/s over a distance of 36 m. What acceleration did it experience? SHOW ALL WORK!

Answer 1

Given:-

• Initial velocity (u) = 0m/s

• Final velocity (v) = 85m/s

• Distance covered (s) = 36m

To Find:-

• Acceleration of the object (a)

Solution:-

By using 3rd equation of motion

→ v² = u² +2as

Substitute the value we get

→ 85² = 0² +2×a×36

→ 7225 = 0 + 72 ×a

→ a = 7225/72

→ a = 100.34m/s²

∴ The acceleration of the object is 100.34m/s²

Additional Information!!

The rate of change of velocity at per unit time is called acceleration .

✧ SI unit of acceleration is m/s²

✧ It is vector Quantity ( both magnitude and direction)