Math, asked by sezalkundu, 1 year ago

an object accelerates from rest to a velocity 30 m/s in 10 s , then find distance covered by the object during next 10 s?

Answers

Answered by garylaupapvsl
8
a=30/10 =3m/s^2

u=30m/s

s=ut+1/2at^2
s=30(10)+1/2(3)(10)^2
s=300+150
s=450m 

The distance covered by the object during next 10 second = 450 meter.

(This is physics, not math)
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