Question

An object accelerates from rest to a velocity of 22 m/s over 35 m. What was its acceleration?

Answer 1

Explanation:

An object accelerates from rest to a velocity of 34 m/s over a distance of 70 m. We want to determine the acceleration.

It is assumed that the acceleration is uniform.

v2=u2+2as, where, v,u,a and s are the final velocity, initial velocity, acceleration and distance, respectively.

It is given that v=34 m/s, u=0 and s=70 m.

⇒342=02+2a×70⇒a=3422×70≈8.257 m/s 2.

⇒ The acceleration is 8.257 m/s ²

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Answer 2

Answer:

a=16.828571...............8571

Explanation:

• given,
• u=0
• v=22m/s
• s=35m
• a=?
• v=s/t
• 22=35/t
• t=35/22
• a=v-u/t
• a=22-0/35/22
• a=22/35/22
• a=22x22/35

a=16.828571...............8571

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