Question

An object accelerates from rest to a velocity of 22 m/s over 35 m. What was its acceleration? the answer should be 6.91. How do you get that?????​

Answer 1

Answer:

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Answer 2

Given :-

• An object accelerates from rest to a velocity of 22 m/s over 25 m.

To find :-

• Acceleration of an object

Solution :-

• Initial velocity (u) = 0

• Final velocity (v) = 22m/s

• Distance covered (s) = 35 m

★ As we know that ★

→ v² = u² + 2as

Where " v " is final velocity, " u " is Initial velocity, " a " is acceleration and " s " is distance covered by an object.

• This is the third equation of motion.

According to the question

→ v² = u² + 2as

→ (22)² = (0)² + 2 × a × 35

→ 484 = 0 + 70a

→ 484 = 70a

→ a = 484/70

→ a = 6.91 m/s²

Hence,

• Acceleration of an object is 6.91 m/s²