Question

an object accelerates from rest to velocity 30 m/s in 10 s , then find distance covered by object during next 10 s ​ An object accelerates from rest to a velocity 30 m/s in 10 s, then find distance covered by the object during next 10 s Options: 450 m 300 m 150 m 600 m

Answer 1

Answer:

Explanation:

v=30 m/s

u=0 m/s

t=10s

by using first equation of motion

v=u+ at

30=0+ a*10

30=10a

a=30/10

a=3m/s^2

then we can find distance by second eqation of motion

s=ut+1/2 at^2

s=0*10 + 1/2 * 3 * 10^2

s=10+ 1/2 *3*100

s=150m

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