An object accelerates from rest with a constant acceleration of 4 m/s2. How far will it have moved after 14 seconds?
Answers
Answered by
1
Answer:
392 m
Explanation:
Initial velocity (u) = 0, acceleration (a) = 4 m/s^2
time (t) = 14 s
Distance moved (s) = ut + 1/2at^2
= 1/2*4*14*14 = 392 m .
Answered by
0
Answer:
(u)initial velocity= 0
(a)acceleration =4m\s2
(t)time = 14s
(s)distance=?
s=ut+1/2at2
=0×14+1/2×4×14^2
=0+392
= 392m
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