Question

an object accelerates uniformly along a straight line with acceleration of 10m/s. at t=0 it is at x= -8m and moving with velocity of 3m/s. what is the position of the object at t=3s?​

Answer 1

Answer:

x=48 m

Explanation:

u(initial velocity)=3m/s a= 10m/s^2 so

by using

S=ut +1/2at^2

x = 3×3 +1/2×10×9

x= 54

but as it is given that object is initially at x=-8m so finally it would be at x=46m

Answer 2

☆your question:-☆

Q) an object accelerates uniformly along a straight line with acceleration of 10m/s. at t=0 it is at x= -8m and moving with velocity of 3m/s. what is the position of the object at t=3s?

☆ your Answer:- ☆

●Given:-

accl^n = 10 m/s^2

t. = 0

x = -8m

u = 3 m/s

t = 3 secso ,

● by using motion formula.

as,

● s = ut + 1/2 at^2

x = 3×3 + 1/2 × 10 × 9

x = 54

but ,

our x = -8 ●so our final distance.

x = 54-8

x = 46so our ans is 46.

☆ THANK YOU ☆