an object accelerates uniformly along a straight line with acceleration of 10m/s. at t=0 it is at x= -8m and moving with velocity of 3m/s. what is the position of the object at t=3s?
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Explanation:
By using the Equations of motion
S=ut+½at²
S=3×3+½×3×(3)²
S=9+27/2
S=45/2
S=24.5 mtrs
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