Question

An object accelerates uniformly along a straight line with an acceleration of 10m/s² . At t=0 , it is at x=-8m and moving with a velocity of 3m/s..... what is the velocity of object at t =3sec and what is the position of object at t = 3 sec​

Answer 1

Answer:

final velocity=33m/sec

final position=46m

Explanation:

Given–

acceptation (a)=10m/sec^2

initially position=x=-8m

initial velocity=u=3m/sec

total time(t)=3sec

final velocity=v

final position=y

Now–

s=ut+at^2/2

y-x=3×3+10×3×3/2

y+8=9+45

y=45+1

y=46m

v=u+at

v=3+10×3

v=33m/sec