Question

an object after travels with a constant velocity of 4m/s for a distance 20m and then moves a further 20m with a constant acceleration of 0.5m/s2 what is the average velocity along the path​

Answer 1

Answer:

4.444...m/s

Explanation:

• For the first case ,v=4m/s

d=20m

we know that, v=d/t

I. e. t=d/v=5s

For the second case.,

u(initial velocity) =4m/s(since the body is moving with constant speed for the first 5second)

a=0.5m/s"2

s=20m

Now, we know that

s=ut +0.5at*2

20=4*t+0.5*0.5t*2

0.25t*2+4t-20=0

t*2+20t-4t-80=0

(t+20)(t-4)=0

t=4(since time cannot be negative)

Now, average velocity

=total distance covered /total time taken

=(20m+20m)/(5s+4s)

=40m/9s

=4.44444...m/s