Question

An object
an
undergoes
accelenation of
50m/s2 starting from rest find
the distance travelled in 7.5 sec​

Answer 1

Answer:

Initial velocity = 0 m/s

Acceleration = 8m/s ²

time taken = 1 sec

And we have to find distance ,

so distance will be,

S = ut+ ½at ²

S = 0 * 1 + ½ *8*1*1

S = 4 * 1

S = 4

Therefore distance traveled = 4 m

I hope it helps…………….

Answer 2

Answer:

187.5

Explanation:

a=50

u=0

v=?

t=7.5

v=u+at

=0+375

{v=375}

now, s=0(7.5)+½×50×7.5

=0+½(50)(75/10)

=½(375)

=187.5