An object and its image are as shown in the diagram below. If the object image distance is 4 cm and the magnification is 3, a)Find the ratio u:v:f.b)What is the type of the lens used
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Explanation:
u=-4(according to sign convention)
magnification=-v/u
3=-v/-4
v=12
lens formula=1/f=1/v-1/u
1/f=1/12-1/-4
1/f=1-3/12
1/f=-2/12
1/f=-1/6
f=-6
ratios=u:v:f=4:12:6=2:6:3
concave lens is used
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